Question

What is the cube of the cube root of 27?​

Answer 1

`{ \sqrt[3]{27} }^(3) \\ we \: can \: solve \: this \: in \: two \: ways \\ 1)cube \: root \: means \: power (1)/(3) \\ so \: { \sqrt[3]{27} }^(3) = { {27}^{ (1)/(3) } }^(3) = {27}^{ (3)/(3) } = 27 \\ 2) { \sqrt[3]{27} }^(3) \\ \sqrt[3]{27} = 3 \\ so \: {3}^(3) = 27 \\ thank \: you`