How many questions I have to ask?

Question

asked Jan 26, 2022 227k views

1 Answer

Mortennobel · Answer 1 · 2022-01-31T19:49:01+0000

Answer:

p is 16

Explanation:

$p \: \alpha {(q + 2)}^(2)$

introduce a constant on a right hand side:

$p = k {(q + 2)}^(2) - - - eqn \: (a)$

[ when q is 1, also p is 1 ]

$1 = k(1 + 2) {}^(2) \\ 1 = 9k \\ k = (1)/(9)$

substitute for k in eqn (a):

$p = (1)/(9) (q + 2) {}^(2)$

so, when q is 10:

$p = (1)/(9) (10 + 2) {}^(2) \\ \\ p = (1)/(9) (144) \\ \\ p = 16$