Question

How many questions I have to ask?​

Answer 1

p is 16

Explanation:

`p \: \alpha {(q + 2)}^(2)`

introduce a constant on a right hand side:

`p = k {(q + 2)}^(2) - - - eqn \: (a)`

[ when q is 1, also p is 1 ]

`1 = k(1 + 2) {}^(2) \\ 1 = 9k \\ k = (1)/(9)`

substitute for k in eqn (a):

`p = (1)/(9) (q + 2) {}^(2)`

so, when q is 10:

`p = (1)/(9) (10 + 2) {}^(2) \\ \\ p = (1)/(9) (144) \\ \\ p = 16`