Question

4:36 PM
How high can a human throw a ball if he can throw it with initial velocity 90 kph

Answer 1

90 km/hr= 90000/3600=25 m/s initial velocity

-25/ 2 (-4.9)= 2.551 secs

h(2.551)= -4.9 (2.551)² + 25(2.551)=-31.8872449+63.775 = 31.8m

The distance would be 31.8 meters, also that person will have sore arm.