Question

Sin A 4/5.

Find
COSA + tan A

Answer 1

Given: SinA = 4/5

To find: CosA + TanA

Solution:
16/25 + Cos²A = 1 [Sin²A + Cos²A = 1]
Cos²A = 1 - 16/25
Cos²A = 25 - 16/25
Cos²A = 9/25
CosA = 3/5
We know that TanA = SinA/CosA
TanA = (4/5)/(3/5)
TanA = 4/3
CosA + TanA = 3/5 + 4/3 = 29/15

Answer 2

Explanation:

The opposite side (the one not connected to A) = 4

The hypotenuse is 5

The adjacent side needs to be found for the cosine and the tangent.

a^2 + b^2 = c^2

a = opposite side = 4

b = adjacent side = ?

c = hypotenuse = 5

4^2 + x^2 = 5^2

16 + x^2 = 25

x^2 = 25 - 16

x^2 = 9

x = sqrt(9)

x = 3

cos(A) = adjacent / hypotenuse = 3/5

Tan(A) = opposite / adjacent = 4/3

cos(A) + tan(A) = 3/5 + 4/3

cos(A) + tan(A) = 9/15 + 20/15 = 29/15