Question

C^-24 times c^9 times c^-87 answer using positive exponents

Answer 1

Explanation:

`a^(m) *a^(n) = a^(m+n)\\\\\ a^(-m)=(1)/(a^(m))\\\\\\c^(-24)*c^(9)*c^(-87)=c^(-24+9-87)\\\\=c^(-102)\\\\=(1)/(c^(102))`

Answer 2

1/c^102

Explanation:

C^-24 * c^9 * c^-87

When we multiply exponents with the same base, we add the exponents

c^(-24+9+-87)

c^(-102)

We know that a^-b = 1/a^b

1/c^102