Question

An interger p is two-third of another and their difference is 10.find the two interferes

Answer 1

30 and 20

Explanation:

We have an integer p and another
`(2)/(3)` p , their difference is 10 , so

p -
`(2)/(3)` p = 10 ( multiply through by 3 to clear the fraction )

3p - 2p = 30 , that is

p = 30

and
`(2)/(3)` × 30 = 2 × 10 = 20

The 2 integers are 30 and 20

Answer 2

30 , 20

Explanation:

Let the other number = x

`p = (2)/(3)x\\`

x - p = 10

Plugin p = (2/3)x in this equation,

`x -(2)/(3)x=10\\\\(3)/(3)x-(2)/(3)x=10\\\\(1)/(3)x=10\\`

Multiply both side by 3

x = 10*3

x = 30

`p=(2)/(3)*30\\\\p= 2 * 10`

p = 20