Answer:
Explanation:
ab² + 2a²b + a³ = a(b² + 2ab + a²)
Here variable 'a' is common in all the terms. HCF = a
2) 2ab² = 2 * a * b *b
4a²b = 2 * 2 *a * a * b
6a³ = 2 * 3 * a * a * a
HCF = 2a
2ab² - 4a²b - 6a³ = 2a(b² - 2ab - 3a²)
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