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X3+y3+z3=k, what replaces k?

User MagB
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Find x, y, and z such that x³+y³+z³=k, for each k from 1 to 100.

On the surface, it seems easy. Can you think of the integers for x, y, and z so that x³+y³+z³=8? Sure. One answer is x = 1, y = -1, and z = 2. But what about the integers for x, y, and z so that x³+y³+z³=42? … I hope it helps you

User JRS
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