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If the refractive index of diamond is 2.42 Find it's critical angle​

User Tklodd
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1 Answer

2 votes

Answer:

Critical angle is 24.4°

Step-by-step explanation:


n \sin(c) = 1

n is refractive index

c is critical angle


{ \sf{2.42 * \sin(c) = 1}} \\ { \sf{ \sin(c) = (1)/(2.42) }} \\ \\ { \sf{ \sin(c) = 0.4132}} \\ { \sf{c = \sin {}^( - 1) (0.4132) }} \\ { \sf{c = 24.4 \degree}}

User Kalpesh Khandla
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