Answer:
Yes
Explanation:
Both arguments are squared so the equation are in the form of a circle.
A lotus is a point that is equidistant from some fixed point of a conic section. This is a circle so the fixed point is called a center of the circle.
The center of the circle is equidistant from any point on the circumference of the circle. In order for a point to be on the circle, it must satisfy the circle equation.
Let plug in what we know
So 3,-4 is on the locus of the circle.