Factorize 2x^2-5/3xy-2y^2

asked Jul 28, 2022 39.1k views

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by Blase

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5 votes

Answer:

$y = 0 \: .x = (2)/(3) y$

Step-by-step explanation:

$\frac{2 {x}^(2) - 5 }{3xy - 2 {y}^(2) }$

$3xy - 2 {y}^(2) = 0$

y * (3x - 2y) = 0

y = 0 = 3x - 2y = 0

y = 0 = 3x = 2y

y = 0

x = (2)/(3) y

$y = 0. \: x = (2)/(3) y$

Dan Randolph answered Jul 30, 2022

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1 vote

I hope it helps you

Carebear answered Aug 3, 2022