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Factorize 2x^2-5/3xy-2y^2

Factorize 2x^2-5/3xy-2y^2
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Factorize 2x^2-5/3xy-2y^2

User Blase
by
8.2k points

2 Answers

5 votes

Answer:


y = 0 \: .x = (2)/(3) y

Step-by-step explanation:


\frac{2 {x}^(2) - 5 }{3xy - 2 {y}^(2) }


3xy - 2 {y}^(2) = 0


y * (3x - 2y) = 0


y = 0 = 3x - 2y = 0


y = 0 = 3x = 2y


y = 0


x = (2)/(3) y


y = 0. \: x = (2)/(3) y

User Dan Randolph
by
8.8k points
1 vote

I hope it helps you

Factorize 2x^2-5/3xy-2y^2-example-1
User Carebear
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