Answer:
D
Explanation:
We have to find the vertex of m(t) = t² - 4t + 25
a = 1
b = 4
c = 25
To do that we first need to move the 25 to the other side by subtracting 25 from both sides
m(t) = t² - 4t + 25
- 25 - 25
m(t) - 25 = t² - 4t
To continue completing the square, we have to add 4 to both sides since it is the square of half of b.
m(t) - 25 + 4 = t² - 4t + 4
m(t) - 21 = t² - 4t + 4
Now, we already found the minimum amount of members, but let's finish the square completion to find the vertex.
m(t) - 21 = t² - 4t + 4
Factor the right side
m(t) - 21 = (t-2)(t-2)
m(t) - 21 = (t-2)²
Finish it by adding 21 to both sides
m(t) - 21 = (t-2)²
+ 21 +21
m(t) = (t-2)² + 21
With this vertex form equation, we can tell that the vertex is (2,21)
Meaning 21 is the lowest number for m(t) for this equation.