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1 vote
Write the equation of the line that passes through the points

(3,-2) and (6, 1).
y=x-5
y = 5x + 1
y = -x + 5

User Matt Kelly
by
7.9k points

1 Answer

5 votes

Answer:

It is y = x - 5

Explanation:

General equation of a line:


{ \bf{y = mx + c}}

m is the gradient, and c is y-intercept.

For gradient:


slope = (y_(2) - y_(1) )/(x _(2) - x_(1))

substitute:


slope = (1 - ( - 2))/(6 - 3) \\ \\ = (3)/(3) \\ slope \: = 1

m = 1

for y-intercept:

consider point (6, 1):


y = mx + c \\ 1 = (6 * 1) + c \\ 1 = 6 + c \\ c = 1 - 6 = - 5

therefore:


{ \sf{equation \: is \: \{y = x - 5 \}}}

User Bgx
by
7.7k points

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