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3) Find the range of the function.

f(x) = -x2 - 5
A) [5,-)
B) (-0,5]
[-5,-)
D) (--, -5]

User Highrule
by
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1 Answer

4 votes

Answer:

Range is (0, -5)

Explanation:


{ \sf{f(x) = - {x}^(2) - 5}}

when x is 0:


{ \sf{f(0) = - 5}}

User DLR
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