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Anyone help me please


( √(x + 1) + √(x - 1) )/( (√(x + 1) - √(x - 1)) ) + ( √(x + 1) - √(x - 1) )/(( √(x + 1) + √(x - 1)) )


User Daaawx
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Answer:

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Anyone help me please ( √(x + 1) + √(x - 1) )/( (√(x + 1) - √(x - 1)) ) + ( √(x + 1) - √(x-example-1
User Joe Bergevin
by
8.5k points
3 votes


\\ \rm\hookrightarrow (√(x+1)+√(x-1))/(√(x+1)-√(x-1))+(√(x+1)-√(x-1))/(√(x+1)+√(x-1))


\sf Let\begin{cases}\sf √(x+1)=a \\ \sf √(x-1)=b\end{cases}

Now


\\ \rm\hookrightarrow (a+b)/(a-b)+(a-b)/(a+b)


\\ \rm\hookrightarrow \frac{\left\{(a+b)(a+b)\right\}+\left\{(a-b)(a-b)\right\}}{(a+b)(a-b)}


\\ \rm\hookrightarrow ((a+b)^2+(a-b)^2)/(a^2-b^2)


\\ \rm\hookrightarrow (a^2+2ab+b^2+a^2-2ab+b^2)/(a^2-b^2)


\\ \rm\hookrightarrow (2a^2+2b^2)/(a^2-b^2)


\\ \rm\hookrightarrow (2(a^2+b^2))/(a^2-b^2)

Put values


\\ \rm\hookrightarrow (2\left[(√(x+1))^2+(√(x-1))^2\right])/((√(x+1))^2-(√(x-1))^2)


\\ \rm\hookrightarrow (2(x+1)(x-1))/((x+1)(x-1))

  • Take 2 common


\\ \rm\hookrightarrow 2\left(((x+1)(x-1))/((x+1)(x-1))\right)


\\ \rm\hookrightarrow 2(1)


\\ \rm\hookrightarrow 2

User FireSarge
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