Question

The length of a rectangle is 10 meters more than its width. If the perimeter of the rectangle is 80 meters, find the dimensions of the rectangle​

Answer 1

Explanation:

L = w + 10

w = w

P = 2w + 2L

P = 80 m

2L + 2w = 80 Substitute for L

2(w + 10) + 2w = 80 Remove the brackets

2w + 20 + 2w = 80 Combine on the left

4w + 20 = 80 Subtract 20 from both sides

4w = 80 - 20

4w = 60 Divide by 4

w = 60/4

w = 15

L = 15 + 10 = 25

Check

2*25 + 2*15

50 + 30

80

So this checks