Question

Pleasse help mee

A rectangular coil of 30 turns has a dimension of 1.0 cm×1.5 cm. The coil experiences a maximum torque of 3.3×10^-4 Nm when placed in a magnetic field of 0.35 T. What is the current in the coil?​

Answer 1

Torque:

τ=NIABsinθ

τ max⇒ θ = 90º

A = 1 x 1.5 = 1.5 cm² = 1.5 x 10⁻⁴ m²

I = τ / NAB

I = 3.3 x 10⁻⁴ / (30 x 1.5 x 10⁻⁴ x 0.35)

I = 0.209 A