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asked Jan 8, 2022 191k views

1 Answer

Keiya · Answer 1 · 2022-01-13T23:36:00+0000

Answer:

3

Explanation:

$log(3x^(3)) - log(x^(2)) = log((3x^(3))/(x^(2)))\\log(27) - log(x) = log((27)/(x) )\\$

therefore,

$(3x^(3) )/(x^(2) ) = (27)/(x) \\3x=(27)/(x) \\3x^(2) =27\\x= +3\\x=-3$

however, since logarithms cannot have negative arguments, x can only be +3

i.e. log(-3) is impossible, and will return MATH ERROR on a calculator.