Question

Please answer this question​

Answer 1

3

Explanation:

`log(3x^(3)) - log(x^(2)) = log((3x^(3))/(x^(2)))\\log(27) - log(x) = log((27)/(x) )\\`

therefore,

`(3x^(3) )/(x^(2) ) = (27)/(x) \\3x=(27)/(x) \\3x^(2) =27\\x= +3\\x=-3`

however, since logarithms cannot have negative arguments, x can only be +3

i.e. log(-3) is impossible, and will return MATH ERROR on a calculator.