Answer:
a) Let x be the cost of one pair of jeans
![4(x-3)+8=92](https://img.qammunity.org/2022/formulas/mathematics/high-school/cu4fnhjq2x7zj6kx501zpqgpvzldo8vogo.png)
b) $24
Explanation:
Given information:
- Cost of t-shirt = $8
- Coupon used for $3 off each pair of jeans
- Total spend = $92 (before tax)
Define the variable:
Let x = the cost of one pair of jeans
Create an equation using the defined variable and the given information:
- Apply the coupon ⇒ cost of one pair of jeans = (x - 3)
- 4 pairs of jeans ⇒ 4(x - 3)
- Plus the cost of the t-shirt ⇒ + 8
- Equals the total cost of ⇒ = 92:
![4(x-3)+8=92](https://img.qammunity.org/2022/formulas/mathematics/high-school/cu4fnhjq2x7zj6kx501zpqgpvzldo8vogo.png)
To find the price of each pair of jeans, solve the equation for x:
![\implies 4(x-3)+8=92](https://img.qammunity.org/2022/formulas/mathematics/high-school/atwh4omk5j2ge43aygbv0tvim8x2gd1pj6.png)
![\implies 4(x-3)+8-8=92-8](https://img.qammunity.org/2022/formulas/mathematics/high-school/eduqbcf5eydkozx6dpju6uv2728bs7fc88.png)
![\implies 4(x-3)=84](https://img.qammunity.org/2022/formulas/mathematics/high-school/k2jy65m2m5g9q18etgf7m4031cvecyvczk.png)
![\implies (4(x-3))/(4)=(84)/(4)](https://img.qammunity.org/2022/formulas/mathematics/high-school/55vyn1r4wpk0i5w55wz622d5zfqbwaiwki.png)
![\implies x-3=21](https://img.qammunity.org/2022/formulas/mathematics/high-school/oavwmtjghsx9bv8ciarhv6xsvhhpa1vm44.png)
![\implies x-3+3=21+3](https://img.qammunity.org/2022/formulas/mathematics/high-school/w06mzxlcv7a0ar7uzmd4oc5bqd6how2lqf.png)
![\implies x=24](https://img.qammunity.org/2022/formulas/mathematics/high-school/jvwxxdklsch0genayj5eoej9lc5nz0o00y.png)
Therefore, the price of each pair of jeans was $24.
----------------------------------------------------
Solving 3(2x - 6) = 4x + 8 mentally:
Expand the brackets:
⇒ 16x - 18 = 4x + 8
Subtract 4x from both sides:
⇒ 12x - 18 = 8
Add 18 to both sides:
⇒ 12x = 26
Two times 12 is 24. As 26 is very close to 24, then x ≈ 2.
(The actual value of x is 2.2 to 2 decimal places).
Assessing the student's solution:
As x = 2.6 rounds to x ≈ 3 then the student's solution is incorrect because:
⇒ 3(2(3) - 6) = 4(3) + 8
⇒ 3(6 - 6) = 12 + 8
⇒ 3(0) = 20
⇒ 0 = 20