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Factorize: 7xyz + 21x^2 y​

User Felickz
by
3.8k points

2 Answers

2 votes

Answer:


7xyz + 21 {x}^(2) y

factorise out 7, x and y:


= 7xy(z + 3x)

User Ganesh Kalje
by
3.3k points
3 votes

Answer:


\huge\boxed{\sf 7xy (z + 3x)}

Explanation:


\sf 7xyz +21x^2y\\\\H.C.F. = 7xy\\\\Hence, \ Take \ 7xy \ as \ common\\\\= 7xy (z + 3x)\\\\\rule[225]{225}{2}

Hope this helped!

~AH1807

Peace!

User Steve Hobbs
by
3.4k points