Question

Factorize: 7xyz + 21x^2 y​

Answer 1

`7xyz + 21 {x}^(2) y`

factorise out 7, x and y:

`= 7xy(z + 3x)`

Answer 2

`\huge\boxed{\sf 7xy (z + 3x)}`

Explanation:

`\sf 7xyz +21x^2y\\\\H.C.F. = 7xy\\\\Hence, \ Take \ 7xy \ as \ common\\\\= 7xy (z + 3x)\\\\\rule[225]{225}{2}`

Hope this helped!

~AH1807

Peace!