Question

Simplify √-18

A 3i√2
B 9i√2
C -3√2

Answer 1

A.
`\displaystyle 3i√(2)`

Explanation:

`\displaystyle √(-18) → √([2][-1][9])\\ \\ 3i√(2)`

As you can see, you need a perfect square to wourk with, which in this case is 9. Now,
`\displaystyle √(-1)` comes out as an imaginary number
`\displaystyle [i],`so pull it out of the radical alongside 3,
`\displaystyle √(9).`

I am joyous to assist you at any time.

Answer 2

`\\ \rm\longmapsto √(-18)`

`\\ \rm\longmapsto √(18)i`

`\\ \rm\longmapsto √(9* 2)i`

`\\ \rm\longmapsto √(3(3)(2))i`

`\\ \rm\longmapsto 3i√(2)`