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g A high-energy photon turns into and electron and a positron. (A positron has exactly the same mass as the electron, but opposite charge.) What is the longest wavelength that the photon can have for this process to occur

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Answer:

2 m = E / c^2 where m is mass of electron

E = h v where v is the frequency ( nu) of the incident photon

E = h c / y where y is the incident wavelength (lambda)

2 m = h / (c y)

y = h / (2 m c) wavelength required

y = 6.62 * 10E-34 / (2 * 9.1 * 10E-31 * 3 * 10E8) m

y = 3.31 / 27.3 E-11 m

y = 1.21 E -12 m = .0121 Angstrom units

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