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5 votes
Find an equation of the line L that contains the points (0,0) and (5,3)

Y =

User Cheeken
by
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1 Answer

6 votes

Answer:

y = (3/5)*x

Explanation:

First, we can use the slope-intercept form of a line, or y=mx+b

To find the slope, m, we can find

(y₂-y₁)/(x₂-x₁). Denoting (0,0) as (x₁,y₁) and (5,3) as (x₂, y₂) (it is perfectly okay to have (0,0) as (x₂, y₂) and (5,3) as (x₁,y₁) as well), we have

(y₂-y₁)/(x₂-x₁) = (3-0)/(5-0) = 3/5

Therefore, our equation is

y = (3/5)x + b

To solve for b, we can plug any value of (x,y) from the line, e.g. (0,0), and solve from there, resulting in

y = mx + b

0 = (3/5)*0 + b

0 = b

Our equation is therefore

y = (3/5)*x + 0

= (3/5)*x

User Aivar Paalberg
by
5.2k points