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what fraction of the Earth's surface would be covered by the surface of the moon,if the radius of the Earth is 6,378km and the radius of the moon is 1.741km?​

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2 votes

Answer:

3031081 / 40678884

Explanation:

To solve this, we can find the surface area of the moon and Earth, and then see how much the moon covers the Earth. The surface area of a sphere is equal to 4πr², so the radius of the Earth is

4πr² = 4 * π * 6378²

and the radius of the moon is

4πr² = 4 * π * 1741²

To figure out how much of the Earth's surface that the moon covers, we can implement a ratio of moons:Earth. This will give us an understanding of how many moons go inside one Earth. We thus have

(4 * π * 1741²) : ( 4 * π * 6378²) = (4 * π * 1741²) / ( 4 * π * 6378²)

cross out the 4 * π in the numerator and denominator

1741²/6378²

Next, we want to make the denominator 1, as that gives us 1 Earth. To do this, we can divide both the numerator and denominator by 6378². Because we are applying the same expression to both the numerator and denominator, this is essentially multiplying the fraction by 1, keeping it the same. We thus have

(1741²/6378²)/(6378²/6378²)

≈0.0745/1

≈ 0.0745

To put this in a fraction, we would have

(1741²/6378²)/1

= (1741²/6378²)

= 3031081 / 40678884

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