Answer:
B)
![x\geq0](https://img.qammunity.org/2022/formulas/mathematics/high-school/h0rht1pb5cipwkk7lbplpt6awh96yyn4yw.png)
Explanation:
The domain of the square root function is all real non-negative numbers. In a numerical format that is as follows:
![D(√(x))={[0,\infty )}](https://img.qammunity.org/2022/formulas/mathematics/high-school/cz3gvs5p8abdi5om9ay8dq2pi6j8d73hlp.png)
This is more commonly denoted as:
![x\geq0](https://img.qammunity.org/2022/formulas/mathematics/high-school/h0rht1pb5cipwkk7lbplpt6awh96yyn4yw.png)
In the case of the given function:
![g(x)=√(8x)](https://img.qammunity.org/2022/formulas/mathematics/high-school/u434kjeulsdtaqmib8f5q7wwtilfb6okne.png)
The domain is still (
) as multiplying a value by (8) does not alter this. A negative number times (8) is still negative and thus cannot be a part of the square root domain. Similarly, a positive number times (8) is still positive and remains a part of the square root domain. Moreover, (0) times (8) is still (0).