Question

Find the remainder when f(x) = x^3- 6x^2 +3x -1 divided by 2x-3

Answer 1

Remainder is -53/8

Explanation:

the divisor is (2x - 3):

make x the subject:

`2x - 3 = 0 \\ 2x = 3 \\ x = (3)/(2)`

substitute for x in the function:

`f(x) = {x}^(3) - 6 {x}^(2) + 3x - 1 \\ f( (3)/(2) ) = {( (3)/(2)) }^(3) - 6 {( (3)/(2)) }^(2) + 3( (3)/(2) ) - 1 \\ \\ f( (3)/(2) ) = ( - 53)/(8)`