Answer:
see below
Explanation:
Part A
The slope is found by
m = ( y2-y1)/(x2-x1)
= ( 1200-1500)/(4-0)
= -300/4
=-75
Part B
point slope y-y1 = m(x-x1) where m is the slope and (x1,y1) is a point on the line
y-1200 = -75(x-4)
slope intercept y = mx+b where m is the slope and b is the y intercept
y = -75x + 1500
standard form Ax+By =C
75x + y = 1500
Part C
Change y to g(x) in the slope intercept form
g(x) = -75x + 1500
Part D
Let x = 5
g(5) = -75(5) + 1500
=-375+1500
=1125