Question

Plzzzz help (wrong answers will be deleted )...(100 points!!)

16x^4−24x^3+3 / 4x^2+3 fill in the boxes(spaces lol) = x^2 - x - + /

Answer 1

`\boxed{\sf (a^m)/(a^n)=a^(m-n)}`

`\\ \rm\Rrightarrow (16x^4-24x^3+3)/(4x^2+3)`

• Take 4x^2+3 common out

`\\ \rm\Rrightarrow 4x^2+3\left((4x^2-24x+1)/(1)\right)`

`\\ \rm\Rrightarrow (4x^2-24x+1)/(1)`

`\\ \rm\Rrightarrow 4x^2-24x+1`

Answer 2

4x² - 24x + 1

Explanation:

`(16x^(4)-24x^(3)+3)/(4x^(2)+3)`

~Factor out the denominator and apply quotient rule [ a^b / a^c = a^b-c ]

`4x^(2)+3 (((16)/(4) x^(4-2)-24x^(3-2)+(3)/(3) )/(1))`

`(4x^(2)-24x+1)/(1)`

~Divide everything by 1

`4x^(2) -24x+1`

Best of Luck!