Question

astone is thrown upwards with an initial velocity of 25m/s atan angle of 30 to the ground.what is the work out the stones horizantal range ?

Answer 1

Range is 62.5 metres

Step-by-step explanation:

Time of flight

`t = (2u \sin( \theta) )/(g)`

for range, acceleration is zero

from second newton's equation:

`S = ut + (1)/(2) {at}^(2)`

but a = 0:

let range be x:

`x = ut \\ x = \frac{2 {u}^(2) \sin( \theta) }{g} \\ \\ x = \frac{ \{2 * 25 {}^(2) \sin(30 \degree) \}}{10} \\ \\ x = 62.5 \: metres`

[ taken g to be 10 m/s² ]