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The concentric circles
(x-3)^2+(y-5)^2=64 and
(x-3)^2+(y-5)^2=25 form a ring. The lines
y=(2)/(3) x+3 and
y=5 intersect the ring, making four sections. Find the area of each section. Round your answers to the nearest tenth of a square unit.

User Ranjith KP
by
3.8k points

2 Answers

7 votes

Answer:

11.5 square unit, 11.5 square wnit
49.8 squave unit, 49.8 square unit

Explanation:


When\ x=3,y=(2)/(3)*3+3=5.


tan(\theta)=(2)/(3)\Rightarrow{\theta}=33.69\ degrees


A_1=\pi(R^2-r^2)\bullet(33.69\ degrees)/(360\ degrees)\\ =\pi(64-25)\bullet(33.69\ degrees)/(360\ degrees)\\ =11.5


A_2=\pi(R^2-r^2)\bullet(180\ degrees-33.69\ degrees)/(360\ degrees)\\ =\pi(64-25)\bullet(146.31\ degrees)/(360\ degrees)=49.8


A_3=A_1=11.5\\ A_4=A_2=49.8


elementany\ calculation

I hope this helps you

:)

User Savvas Dalkitsis
by
4.0k points
6 votes

Hi,

Please check the attached picture of the explanation...

Thank you!

The concentric circles (x-3)^2+(y-5)^2=64 and (x-3)^2+(y-5)^2=25 form a ring. The-example-1
User Louis CAD
by
3.7k points