Question

Does anyone know how to do this

Answer 1

The solution is B

Explanation:

`x + 5 \geqslant 1 \\ x \geqslant 1 - 5 \\ x \geqslant - 4`

then:

`x - 7 < - 3 \\ x < - 3 + 7 \\ x < 4`

therefore, interval [limits] of x:

`- 4 \leqslant x < 4`