Question

1. I am a five digit number

2. Each digit is even and unique
3. I am divisible by 10
4. My fourth digit is half as much as my second digit
5. My third digit is three times as much as my first digit

Please help me solve this riddle. Please do not directly give me the answer.

Answer 1

Answer: is 65292

1.Three pairs of digit sum up to 11

So.5+6,4+7,3+8,2+9

So, password must consist of 2 to 9 numbers to make a pair 11.

No 0 or 1.

2.Also it has only 5 digit. So any two number must be same.

3. as per other condition.. 1st and last digit can't be same and also 3 middle digits can't have 2 same number.

4. Last and first digit can be

6___2

9___3

No other options suit for three times the last digit.

5. For middle numbers..

_529_ is the only option and 2 is a repeator that can make third pair as sum of 11.

_63(11)_ error and also 6 is a repeator but it can't make sum as 11.. Anyway error case.

_74(12)_error also no repeators

So.. Now from step 4 and 5..

65292 is the password.

Answer 2

1) 5 digits= 10,000

2) Even numbers, so no 1,3,5,7 or 9. Only 2,4,6,8 and 10

3) Can be divided by 10

4) We need to divide the 2nd digit by 2 to find the 4th digit

5) We need to multiply the 3rd digit divided by 3 to find the 1st digit

If you need help or the answer, I can help!

I recommend to start like this:

1) Remeber: It's in the 10,000 and is an even number (You can write it down)

2) Start with using step number 5) above! Only use numbers 2,4,8 and 10, cannot reused once used!

3) Go on step 4) above

4) Divide it by 10 to check and if it can be divided (meaning no fraction or extras!) That's your answer!

I really hope I've help!