Answer:
8 gallons
Explanation:
The function that would describe the amount of water in the pool at time x (in minutes) would be comprise of two terms:
1. An initial term, I, that accounts for water already present at the start of time, x, and
2. water added by a hose with a rate of 4 gallons/minute would constitute a term of 4x
The equation, f, that provides the gallons in the pool is given by:
f(x) = I + 4x, where I is the initial amount of water (gallons) and 4x is a rate of 4 gallons/min times the number of minutes the hose is functioning.
If the pool was initially empty, the amount of water in the pool after two minutes would be:
f(2) = 0gal + 4gal/min(2 minutes)
f(2) = 8 gallons