W(x) = x2 + 1; Find w(x + 3)

Question

asked Oct 3, 2022 42.2k views

1 Answer

Salva Corts · Answer 1 · 2022-10-07T15:40:19+0000

Given the function w:

$\displaystyle \large{w(x) = {x}^(2) + 1 }$

Since we want to find w(x+3), the input would be x+3.

Substitute x = x+3 in.

$\displaystyle \large{w(x + 3) = {(x + 3)}^(2) + 1 }$

Alternate Solution

The answer above works if you want it in vertex form. For this alternate solution, I will convert the function in standard form.

As we know:

$\displaystyle \large{ {(x + y)}^(2) = {x}^(2) + 2xy + {y}^(2) }$

Therefore:

$\displaystyle \large{ {(x + 3)}^(2) = {x}^(2) + 2(x)(3) + {3}^(2) } \\ \displaystyle \large{ {(x + 3)}^(2) = {x}^(2) + 6x+ 9}$

Now for function w:

$\displaystyle \large{w(x + 3) = {x}^(2) + 6x + 9+ 1 } \\ \displaystyle \large{w(x + 3) = {x}^(2) + 6x + 10}$

Hence: