Question

An excess of a divalent metal M was dissolved in a limited volume of hydrocloric acid. If 576cm³ of hydrogen was librated at s.t.p , what was the mass of metal that produced this volume of gydrogen?( M = 24, H = 1 , molar volume of gas at s.t.p = 22.4dm³)​

Answer 1

14.8 g

Step-by-step explanation:

step 1 You first have to convert the cm^3 to dm^3 by dividing the volume by 1000 then find the number of mols for Hydrogen gas

from there you can use the of moles for hydrogen to find the moles of the metal step 2

then step 3 you multiply the number of by The Mr or Fr giving you your mass