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Which of the following values are solutions to the inequality 3x+10\ge 2?3x+10≥2?

\text{I.}\hspace{2px}-1\hspace{20px}\text{II.}\hspace{2px}3\hspace{20px}\text{III.}\hspace{2px}-11
I.−1II.3III.−11

\text{None}None
\text{I only}I only
\text{II only}II only
\text{III only}III only
\text{I and II}I and II
\text{I and III}I and III
\text{II and III}II and III
\text{I, II and III}I, II and III

User WorieN
by
8.6k points

1 Answer

5 votes

9514 1404 393

Answer:

I and II

Explanation:

The inequality ...

3x +10 ≥ 2

has solutions ...

3x ≥ -8 . . . . . . . . subtract10

x ≥ -2 2/3 . . . . . divide by 3

Of the answer choices {-1, 3, -11}, the ones that are greater than -2 2/3 are ...

-1, 3 . . . . . . I and II only

User Nate Hekman
by
8.8k points
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