Question

What is the vertex of the parabola with the equation y=15x2+2x−8?

Answer 1

a =15, b=2

Axis of Symmetry =
`(-b)/(2a)`

`=(-2)/(2 * 15)`

=
`-(1)/(15)`

To find the y-value for the vertex sub in the axis of symmetry for x

`y=15(-(1)/(15) )^(2)+2(-(1)/(15) )-8\\\\=-(121)/(15)`

∴ Vertex
`(-(1)/(15), -(121)/(15) )`

Explanation: