1 Answer

CristiCh · Answer 1 · 2022-07-07T19:12:51+0000

Explanation:

This equations are quadratic equations, which is on standard form,

${ax}^(2) + bx + c$

where a is the leading coefficient, b is the second coefficient, and c is the constant.

Both a and b are in quadratic equation so we need to find the constant separately.

Both sides are equal to zero so we can just subtract the terms not containing a or b in them to the opposite side.

${x}^(2) - 4 x + a = 0$

${x}^(2) + a = 4x$

$a = - {x}^(2) + 4x$

For b,

$2 {x}^(2) - 6x + b + 7 = 0$

$- 6x + b + 7 = - 2 {x}^(2)$

$b + 7 = - 2 {x}^(2) + 6x$

$b = - 2 {x}^(2) + 6x - 7$

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