Question

Jesse travels 3.0 meters east and then turns and travels 4.0 meters north. The trip requires 35 seconds. What is his velocity?

Answer 1

Using Pythagorean triplet

`\\ \sf\longmapsto AB^2=AC^2-BC^2`

`\\ \sf\longmapsto AB^2=4^2-3^2`

`\\ \sf\longmapsto AB^2=16-9`

`\\ \sf\longmapsto AB^2=7`

`\\ \sf\longmapsto AB=√(7)`

• Now time=35

`\\ \sf\longmapsto Velocity=(Displacement)/(Time)`

`\\ \sf\longmapsto Velocity=(√(7))/(35)`

`\\ \sf\longmapsto Velocity=(2.6)/(35)`

`\\ \sf\longmapsto Velocity=0.07m/s`