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5 votes
For real numbers x and y, what is the largest possible value of
5 - (x-3)^2?

User Dvdgsng
by
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1 Answer

2 votes

Answer:

5

Explanation:

Anything other than making x - 3 = 0 will make x - 3 have a value. No matter what happens (x - 3)^2 is positive. There is a minus sign outside the brackets which makes (x - 3)^2 negative.

That means that something is always taken away from 5 unless x = 3. Try and find any value that will make a number bigger than or equal to five that isn't x = 3.

By the way, I'm assuming the question is y = 5 - (x - 3)^2

User Deepakraut
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6.9k points