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11. The rectangle has a width of 8 in, a length of x-5 in, and an area of 16 in. Solve for X.

Hint: label the figure.
K-5in
8in

11. The rectangle has a width of 8 in, a length of x-5 in, and an area of 16 in. Solve-example-1
User Sebrina
by
4.0k points

2 Answers

4 votes

Answer: x =

Explanation:

Area = width times length

8*(x-5)=16

8x - 40 = 16

8x = 16 + 40

x = 56/8

x = 7

User Md Nasir Fardoush
by
4.4k points
4 votes

Area = width × length

16= 8 × (X –5 )

16 = 8X – 40

8X = 16 + 40

8X = 56

X= 56 / 8

X= 7 in

I hope I helped you^_^

User Livven
by
3.6k points