Question

An object starts from rest with constant acceleration of 8m/s2

along a straight line. Find The distance travelled during the 5th second.

Answer 1

• Initial velocity=u=0m/s
• Acceleration=a=8m/s^2
• Time=t=5s
• Distance=s=?

Using second equation of kinematics

`\boxed{\sf s=ut+(1)/(2)at^2}`

`\\ \qquad\quad\sf{:}\dashrightarrow s=0(5)+(1)/(2)(8)(5)^2`

`\\ \qquad\quad\sf{:}\dashrightarrow s=4(25)`

`\\ \qquad\quad\sf{:}\dashrightarrow s=100m`