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Please help step by step.

Please help step by step.-example-1
User Rcoup
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Answer:

(a) CG·CE = CH·CD

(b) DH = 3 in

Explanation:

a)

From the common point, the product of distances to the near and far intersections with the circle is the same for both secants:

CG·CE = CH·CD

__

b)

It is possible to find HD given the information.

(4 in)(4 in +6 in) = (5 in)(5 in + DH) . . . . . . fill in the given values

40 in² = 25 in² +(5 in)(DH) . . . . simplify

15 in² = (5 in)(DH) . . . . . . . subtract 25 in²

3 in = DH . . . . . . . . . . . divide by 5 in

Please help step by step.-example-1
User Bejado
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