Answer:
![\displaystyle y = -4x - 5](https://img.qammunity.org/2022/formulas/mathematics/high-school/w3u8jmdf6frrnwa0gkacbhvjx1vrk0h62c.png)
Explanation:
We want to find the slope-intercept form of the equation that passes through the point (-2, 3) and is perpendicular to the line:
![\displaystyle y = (1)/(4) x - 4](https://img.qammunity.org/2022/formulas/mathematics/high-school/zshvbw4n9tkpueuohuuct4tw7wfaoz8hri.png)
Note that this line has a slope of 1/4.
Recall that the slopes of perpendicular lines are negative reciprocals of each other.
Since the slope of our old line is 1/4, the slope of its perpendicular line must be -4.
We are also given that it passes through the point (-2, 3). So, we can consider using point-slope form:
![\displaystyle y - y_1 = m(x - x_1)](https://img.qammunity.org/2022/formulas/mathematics/high-school/pwx8duttzwi0m7uovt992secx3jvg85bd7.png)
Let (-2, 3) be (x₁, y₁) and substitute -4 for the slope m. Hence:
![\displaystyle y - (3)= -4 (x - (-2))](https://img.qammunity.org/2022/formulas/mathematics/high-school/q57zwgre435qxmpn81yb9ftk4xyirbj7re.png)
Convert into slope-intercept form. Simplify:
![\displaystyle \begin{aligned} y -3 &= -4 (x + 2) \\ y - 3 &= -4x - 8 \\ y &= -4x -5\end{aligned}](https://img.qammunity.org/2022/formulas/mathematics/high-school/hxy56peg2byprm6cn1h4gabu9tyxdibn3c.png)
In conclusion, the perpendicular line that passes through the point (-2, 3) is given by:
![\displaystyle y = -4x - 5](https://img.qammunity.org/2022/formulas/mathematics/high-school/w3u8jmdf6frrnwa0gkacbhvjx1vrk0h62c.png)