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3 votes
HCF of (a^3+b^3 ) & (a^4+a^2b^2+b^4)?

User Endofzero
by
4.3k points

2 Answers

5 votes

Answer:

Explanation:

Remember:


a^3+b^3=(a+b)(a^2-ab+b^2)\\


a^3+b^3=(a+b)(a^2-ab+b^2)\\\\\\a^4+a^2b^2+b^4=a^4+2a^2b^2+b^4-a^2b^2\\\\=(a^2+b^2)^2-a^2b^2\\\\=(a^2+b^2-ab)(a^2+b^2+ab)\\\\HCF=a^2+b^2-ab\\

User Roman Sterlin
by
4.7k points
4 votes

Answer:

a^2-ab+b^2

Explanation:

factorize both of them.

User StenaviN
by
5.2k points