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The coordinates of the three vertices of the triangle are A (x1, y1), B (x2, y2), C (x3, y3).

Point D divides AB into internal division ratio I:k, E point divides DC internal division ratio m : k+1, find the coordinates of point E.

Really don't know how to solve this, hope someone can help, thank you very much.​

1 Answer

4 votes

Answer:

Explanation:

Using the section formula, if a point (x,y) divides the line joining the points (x

1

,y

1

) and (x

2

,y

2

) in the ratio m:n, then

(x,y)=(

m+n

mx

2

+nx

1

,

m+n

my

2

+ny

1

)

The vertices of the triangle are given to be (x

1

,y

1

),(x

2

,y

2

) and (x

3

,y

3

). Let these vertices be A,B and C respectively.

Then the coordinates of the point P that divides AB in l:k will be

(

l+k

lx

2

+kx

1

,

l+k

ly

2

+ky

1

)

The coordinates of point which divides PC in m:k+l will be

m+k+l

mx

3

+(k+l)

(l+k)

lx

2

+kx

1

,

m+k+l

my

3

+(k+l)

(l+k)

ly

2

+ky

1

⇒(

m+k+l

kx

1

+lx

2

+mx

3

,

m+k+l

ky

1

+ly

2

+my

3

)

User Dhaval Pandya
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