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Find the constant C such that x ^ 3 - 3x + 5 <= C where x in[0,3] 18 23 14 17 21

Find the constant C such that x ^ 3 - 3x + 5 <= C where x in[0,3] 18 23 14 17 21-example-1

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Plug in maximum value of x (3) and see what you get. The maximum value of the expression when plugged in is C.


3^3-3\cdot3+5=C


27-9+5=C\implies 23=C

Now that means,


x^3-3x+5\leq 23 for any x in
[0,3]

Hope this helps :)

User Nicolas Bossard
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