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The H.C.F. of m²-n² and (m-n)² is ...

User Dwilbank
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1 Answer

2 votes

Answer:

(m-n)

Explanation:

1st expression=


= {m}^(2) - {n}^(2) \: \: \: \: \: \: \: \: \: \:

=(m-n) (m+n)

2nd expression=


({m - n})^(2)

=(m-n)(m-n)

therefore H.C.F=(m-n)

taking common (m-n)

User Vintesh
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