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Solve each proportion

Solve each proportion-example-1

2 Answers

7 votes

Answer:


(11)/(b - 1) = (6)/(b + 1) \\ 11(b + 1) = (b - 1).6 \\ 11b + 11 = 6b - 6 \\ 11b + 11 - 11 = 6b - 6 - 11 \\ 11b - 6b = 6b - 17 - 6b \\ 5b = - 17 \\ (5b)/(5) = ( - 17)/(5) \\ b = ( - 17)/(5) \\ b = - 3.4

User Srividya
by
8.2k points
5 votes


\boxed{\underline{\bf \: Answer}}


\sf (11)/(b + 1) = (6)/(b + 1) \\

Multiply both sides of the equation by
\left(b-1\right)\left(b+1\right), the least common multiple of b-1,b+1.


\sf\left(b+1\right)* 11=\left(b-1\right)* 6

Use the distributive property to multiply b+1 by 11.


\sf11b+11=\left(b-1\right)* 6

Subtract 6b from both sides.


\sf11b+11-6b=-6

Combine 11b and -6b to get 5b.


\sf5b+11=-6

Subtract 11 from both sides.


\sf5b=-6-11

Subtract 11 from -6 to get -17.


\sf5b=-17

Divide both sides by 5.


\sf \: b=\bf(-17)/(5)

=> The correct answer is
\bf \: b=(-17)/(5) or
\bf \: b= -3.4 (✓).

__________

Hope it helps.

RainbowSalt2222

User Muhammad Amjad
by
8.2k points

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