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Write an equation in slope-intercept form of the line passing through (0, 3) and (2, -1).

y=2x+3y=2x+3

y=-2x+3y=−2x+3

y=-2xy=−2x

y=-x+3y=−x+3

1 Answer

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Hi there!

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I believe your answer is:


y = -2x + 3

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Here’s why:

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\boxed{\text{Slope-Intercept Form Is:}}\\\\y=mx + b\\---------------\\\boxed{\text{Key:}}\\\\m - slope\\b - y-intercept\\---------------\\\boxed{\text{\underline{Known Information:}}}\\\\\rightarrow \text{We are given the points: } (0,3) \text{ and } (2, -1)\\---------------\\\boxed


\boxed{\text{\underline{Y-Intercept:}}}\\\\\rightarrow \text{Since the line passes at point (0, 3), the y-intercept would be 3.}\\---------------\\\boxed{\text{\underline{Slope:}}}\\\\\rightarrow m =(rise)/(run)=(y_2-y_1)/(x_2-x_1) \\\\\rightarrow m = (-1-3)/(2-0)=(-4)/(2)=\boxed{-2}\\\\\text{The slope is: } \boxed{-2}\\---------------


\boxed{\text{\underline{Equation:}}}\\\\\text{Our equation should be:}\\\\y = -2x + 3

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Hope this helps you. I apologize if it’s incorrect.

User Nightfirecat
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